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2X 3Y 9 In Slope Intercept Form

2X 3Y 9 In Slope Intercept Form - Rearrange the equation by subtracting what is. X^ {\msquare} \log_ {\msquare} \sqrt {\square} \nthroot [\msquare] {\square} \le. Y = − 2 3x+3. In the equation y = mx + c, m is the slope,. In slope intercept form 3y = 2x + 9 y = ( 2x + 9)/3 y = 2/3 x + 3. To do that, we just multiply both sides times x minus four. Web this form of the equation is very useful. C is the intercept which is the point at x = 0 where the line cuts the y axis. 2x + 3y = 9 2 x + 3 y = 9. So we get our equation into this form:

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See a solution process below: Rearrange the equation by subtracting what is. Y = − 2 3x+3. 2x + 3y = 9 2 x + 3 y = 9. In slope intercept form 3y = 2x + 9 y = ( 2x + 9)/3 y = 2/3 x + 3. C is the intercept which is the point at x = 0 where the line cuts the y axis. So we get y minus 9, we get y minus nine is. The coefficient of x (the m value) is the slope of the line. Web click the blue arrow to submit and see the result! X^ {\msquare} \log_ {\msquare} \sqrt {\square} \nthroot [\msquare] {\square} \le. So we get our equation into this form: To do that, we just multiply both sides times x minus four. In the equation y = mx + c, m is the slope,. Web y = mx + c. Web this form of the equation is very useful.

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